Hyperlyceum.com

How to Solve and Debug Common Abaqus Errors (A Comprehensive Guide): Part-1

Abaqus errors content-1
Share This Post

Welcome to our blog dedicated to unraveling the mysteries of Abaqus errors and empowering users with practical solutions! Whether you’re a novice just beginning your journey into finite element analysis or a seasoned pro seeking to sharpen your problem-solving skills, navigating the complexities of Abaqus can often feel like a daunting task. From perplexing error messages to unexpected model behaviors, challenges pave the road to mastering Abaqus.

In this blog, we aim to demystify the most common Abaqus errors encountered by users at all levels and provide actionable strategies to overcome them. Drawing upon our collective expertise and real-world experiences, we’ll delve into the intricacies of error interpretation, troubleshooting techniques, and best practices for optimizing model settings.

Join us as we explore the fascinating world of Abaqus errors, learn from our mistakes, and uncover the keys to achieving accurate and reliable simulations. Whether you’re seeking guidance on resolving specific error codes or simply looking to enhance your problem-solving ability, this blog is your go-to resource for mastering Abaqus and unlocking its full potential.

So, buckle up and get ready to embark on a journey of discovery as we dive deep into the realm of Abaqus errors and pave the way to success together!

Too many attempts made for this increment

It’s a perplexing issue, stemming from various sources and proving resilient to resolution! This error crops up specifically in Abaqus’ Static General solver and is closely tied to the problem-solving methodology inherent in this solver. The iterative process of trial and error within the Newton-Raphson method, coupled with the solver’s pursuit of convergence, sets the stage for encountering this error during solution iterations.

Too many attempts Abaqus error

As outlined earlier, I suggest initially scrutinizing the load range and unit coordination. Additionally, if the issue persists, a straightforward approach involves tweaking the minimum and maximum Time Increment values; however, this workaround typically yields little success, often resulting in the solution process being prematurely halted with the same error message.

Given that pushing through the solution in scenarios involving significant deformations can spell complete demise for certain elements, one potential remedy involves refining elements in these problematic regions or, alternatively, employing a suitable Damage criterion to exclude these elements from analysis, thus preempting further complications down the line.

Nevertheless, it’s worth acknowledging that even these proposed solutions may fall short in some instances, leaving the problem stubbornly unresolved. My recommendation? If you possess a solid grasp of Explicit solver usage conditions and the problem context supports it, consider switching to Abaqus/Explicit (with due consideration given to all pertinent factors and the solution’s conditional stability).

Also you can see the following video, for more information about this error:

You can purchase this complete tutorial video now!

Time increment required is less than minimum specified

The error originates from multiple sources, with the most common culprit often being the application of loads onto the component. If the displacement or force exerted on the component exceeds the allowed range, or if the values inputted in the Abaqus Load module don’t match the mechanical properties defined in the Property module in terms of units, you’ll encounter this error message.

Time increment required is less than the minimum specified Abaqus error-1

To resolve this issue, start by examining these factors and ensuring consistency between units and the permissible loading range of the component. If no discrepancies are found, proceed to the Step module and adjust the solver settings by decreasing the value of the minimum increment size parameter to a smaller value, such as 1e-9.

Time increment required is less than the minimum specified Abaqus error-2

For more information, you can watch the tutorial provided below:

Missing Property Definition

You can find the root cause of this error in the Abaqus Property module. If you’ve forgotten to assign a material to your component in the Property module, you’ll encounter the “Missing Property Definition” error.

Missing property Abaqus error-1

I recommend also exploring the Warning tab for precise insights into the cause of the error. If you haven’t assigned a cross-sectional area to the body in the Property module, you’ll face a similar error message. To resolve this, simply return to the Property module and define an appropriate cross-sectional area for the component.

Missing property Abaqus error-2

Furthermore, it’s possible that you’ve defined a cross-sectional area like “Truss” for your component in the Property module but haven’t assigned Truss elements to it in the Mesh module. In this scenario, you’ll encounter a similar error, but in the Warning tab, you’ll see a message similar to the one shown below.

Missing property Abaqus error-3

To address this issue, navigate to the Mesh module and assign the appropriate elements with the desired cross-sectional area to the component.

No Density has been specified

You’re probably aware that when using the Abaqus/Explicit solver, you need to define the density for the respective material in the Property module. However, if for any reason you forget to input the density of your desired material, you’ll encounter the following error.

It’s evident that based on the above explanation, to rectify this error in Abaqus, you must navigate to the Property module and input the material density value.

No density specified

Linear kinematic hardening requires two yield stress values

Material hardening in the plastic region is one of the most common phenomena that researchers and industrialists consider to enhance the quality and precision of their analyses. However, if you also decide to incorporate kinematic hardening in the stress-strain curve’s plastic section, you may encounter a similar error as shown below.

Linear kinematic hardening Abaqus error-1

But where does the origin of this error lie? Just focus on the provided text. According to the established pattern for software, when defining kinematic hardening in a bilinear manner, we need to specify stress values in two separate lines during the definition of material mechanical properties in the Property module. Therefore, to rectify the above error, access the Property module and, as depicted below, amend the mechanical properties related to kinematic hardening.

Linear kinematic hardening

Too many increments needed to complete the step

This error occurrence stems from an insufficient number of increments necessary for problem resolution in Abaqus. To address this issue, revisiting the Abaqus Step module and augmenting the maximum number of steps is imperative.

Too many increment Abaqus error

NO Step Definition

If you forget to define the time step and your desired solver in the Step module, you’ll encounter an error similar to the one shown below:

No step definition

As evident from the error message, the solution time step for the problem is not defined. To resolve this error in Abaqus, you need to navigate to the Step module and select the appropriate solver for your problem. Remember that boundary and initial conditions, loading, and contact definition are also linked to the Step module; therefore, any changes made in the Step module must be considered in the Interaction and Load modules as well, and if necessary, adjustments should be made.

In the next article, we will explore other common errors in Abaqus. Stay tuned with us!

More To Explore

Leave a Reply

Your email address will not be published. Required fields are marked *

Subscribe To Our Newsletter
Get updates and learn from the best

Table of Contents

Do you need help from experts?
drop us a line and keep in touch